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- #Pick a number between 1 and 3 10 times how to#
- #Pick a number between 1 and 3 10 times mod#
- #Pick a number between 1 and 3 10 times code#
#Pick a number between 1 and 3 10 times mod#
Sequences mod 2^32 or 2^64, particularly well suited to Random number generator, and it seems to provide quite satisfactory This is an example of my "multiply-with-carry" The arithmetic is simple enough to carry out in your head. The "random digits" are the units digits of the 2-digit numbers, Residues relatively prime to the modulus, 10. Īnd its period is the order of the multiplier, 6, in the group of Although those are still relatively predictable since most people would probably make their selection from the small set of well-known irrational numbers, so you should go one step further and add to or multiply the value.įor ease of reference, here is the text at that link verbatim:Ĭhoose a 2-digit number, say 23, your "seed". The best choice is probably an irrational number like the square root of two (√2) or pi (π). It's also interesting that most people will limit their choice to a (whole number | positive integer).
![pick a number between 1 and 3 10 times pick a number between 1 and 3 10 times](https://media.cheggcdn.com/study/eef/eef8e975-b1c8-4a89-8530-921d79e96ece/image.png)
Does this question and answer pair give anyone else a strong feeling of déjà vu? I think this interaction is a meme. This was immediately followed by the thought that if I were the one picking a number I should explicitly avoid seven. When I encountered the question the first number that popped into my head was also seven. "It's between one and a lot," he added, helpfully. > "What number am I thinking of?" repeated Mr. Then, you just substitute the 6 for ATTEMPTS_FOR_LOST in the conditional snippet I showed a little above.This past week I was reading Neverwhere, by Neil Gaiman which has the same interaction: If we, on the other hand, want to replicate a sequence (e.g.
#Pick a number between 1 and 3 10 times code#
Repat a sequence of numbers: rep (c ( 1, 2, 3 ), times 10) Code language: R (r) Save.
#Pick a number between 1 and 3 10 times how to#
Here’s how to repeat a sequence of numbers. That is done like this: ATTEMPTS_FOR_LOSE = 6 In this example, we are going to get the numbers 1, 2, 3 generated 10 times. You can pick any number to generate a random number in between those numbers. Then, to take this step further and reduce magic numbers, create a constant at the top of your code that defines the number of attempts at which the user has lost. Then, at the end of your code and after the loop, you just need to set up some simple conditionals that check the attempts variable: if attempts < 6: Then, every time the code loops (they enter an answer), you just increment the counter: num = random.randint(1, 100) This can be done by using a simple counter for how many times the user has made an attempt. You should actually count up and tell the user if they won. Why are you splitting this on to two different lines? You can just merge the int() onto the line above it, and pass input() into it like this: guess = int(input())Īs Greg Hewgill mentioned in the comments, rather than saying this: print('if you gussed less than 6 times you won') This is not a very extensible design, again, I'd recommend creating a function that allows you to create custom games, like this: def number_guessing_game(low, high, rounds):
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![pick a number between 1 and 3 10 times pick a number between 1 and 3 10 times](http://cdn-webimages.wimages.net/04ebb802dc42743418124359d63a131539a6d0-wm.jpg)
(This has been implemented below, for reference.) The easiest way to do this would be to use a for. Rather than printing a message saying that if the user got below a certain amount of tries, they win, you can implement it into the code. Print("Guess a number between 1 and 100.") To set up something like this in your code, you'd change your code to something like this. User_integer = input("Enter an integer: ") What you need to do is set up a try- except block, like this: try: What do you suppose happens if the user enters something like "abc"? Right now, as it stands, you're just converting any user input to a integer, using the int function.